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Active Sallen-Key 2nd-Order Low-Pass Filter Cutoff & Q Calculator

The Sallen-Key topology is an active second-order filter configuration that utilizes a unity-gain operational amplifier buffer and two RC sections.

Calculated Result
1500.5 Hz

Cutoff Frequency (f_c)

Quality Factor (Q)

0.707

Damping Ratio (ζ)

0.707

Filter Approximation Alignment

Butterworth (Maximally Flat Passband, Q ≈ 0.707)

Calculation Breakdown

  1. f_c = 1 / (2π·√(R₁·R₂·C₁·C₂))1500.5 Hz
  2. Q = √(R₁·R₂·C₁·C₂) / [C₂·(R₁ + R₂)]0.707

What Is the Active Sallen-Key 2nd-Order Low-Pass Filter Cutoff & Q Calculator?

The Sallen-Key topology is an active second-order filter configuration that utilizes a unity-gain operational amplifier buffer and two RC sections.

The component ratios R1, R2, C1, and C2 uniquely determine the natural frequency f_0 and quality factor Q, establishing maximally flat (Butterworth) or linear-phase (Bessel) response.

How Does the Active Sallen-Key 2nd-Order Low-Pass Filter Cutoff & Q Calculator Work?

The calculation evaluates user-provided measurements using recognized domain equations, converts between measurement units, and adjusts for real-world efficiency factors.

Active Sallen-Key 2nd-Order Low-Pass Filter Cutoff & Q Calculator Formula & Variables

The core mathematical equation utilized by this calculator is expressed as:

f_c = 1 / [2π · √(R₁ · R₂ · C₁ · C₂)], Q = √(R₁·R₂·C₁·C₂) / [C₂·(R₁ + R₂)]

Evaluates second-order denominator polynomial s² + (ω_0/Q)s + ω_0² for unity-gain non-inverting Sallen-Key stage.

How to Use the Active Sallen-Key 2nd-Order Low-Pass Filter Cutoff & Q Calculator

  1. Enter your primary measurements in the input fields above.
  2. Select your preferred units (e.g. metric or imperial) if applicable.
  3. Review or adjust operational assumptions such as field efficiency.
  4. Click Calculate to instantly generate the full results breakdown and visual chart.
  5. Use the Reset button at any time to clear the form and test a new scenario.

Step-by-Step Example Calculation

Butterworth-aligned audio low-pass filter with R = 10 kΩ, C₁ = 15 nF, C₂ = 7.5 nF

Input Values:

resistorR1Ohms:10000
resistorR2Ohms:10000
capacitorC1Farads:1.5e-8
capacitorC2Farads:7.5e-9
Worked Steps: With C₁ = 2·C₂, the filter achieves Q = 0.707 (maximally flat Butterworth response) with cutoff f_c ≈ 1,500 Hz.

Understanding Your Result

Your calculated result represents the realistic operational capacity or baseline output under the specified conditions. Comparing theoretical and effective outputs reveals the direct impact of turns, overlap, and practical downtime.

Factors That Affect the Result

Field terrain, operator experience, equipment maintenance, overlap margin, and weather conditions can significantly influence real-world output.

When Should You Use This Calculator?

Use this calculator whenever you need quick, verified estimates for job planning, budgeting, equipment sizing, or project timelines.

Assumptions & Limitations

  • Analog Filters
  • Signal Processing
  • Audio Engineering

Frequently Asked Questions

Calculation Accuracy & Reference Note

This calculator implements verified, deterministic mathematical equations based on published standards. Results should be treated as professional engineering estimates; always verify critical operations with local equipment manuals and site inspections.

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